Next Palindrome number

[Avantika_Sharmaa24]

Can you help me figure out what is causing an issue with my programming code as I am new to this?
If the number entered by the user (n) is not a palindrome, I want to print the next palindrome number.
I have taken the reference of this problem from this problem post.

Code:

n = int(input("Enter any number :- "))

reverse = 0
temp = n

while (n!=0):
    reverse = reverse * 10
    reverse = reverse + n%10
    n=n//10
if(temp==reverse):
    print ("Already palindrome:: ")

if(temp != reverse):
     new_temp = temp
     new_reverse = 0
     for i in range(new_temp,new_temp+10):
        while(temp != 0):
            new_reverse = new_reverse * 10
            new_reverse = new_reverse + temp%10
            temp = temp//10
         if(new_temp==new_reverse):
             print ("Next pallindrome is :- ",new_temp)
             break
         if(new_temp != new_reverse):
             temp = new_temp+1

[SectorVector]

Line 21 and Line 25: Indentation error. That is easily fixed.

Now, try adding a print after line 17 (which is the while loop)
print the values of temp and new_reverse.

Input a 2 digit number; say 15. Watch the output. See if you can figure it out.

Hint: What does 'i' do.

There are other problems with the code. But see if you can solve this by yourself first. This will help in the long run.